an integer is the next variable on the stack, then printf() will output garbage. additional arguments − Depending on the format string, the function may expect a sequence of additional arguments, each containing one value to be inserted instead of each %-tag specified in the format parameter (if any). 518. 1. printf() function in C language: In C programming language, printf() function is used to print the (“character, string, float, integer, octal and … You can see this question on Stackoverflow: for scanf: %f is float, %lf is double, %Lf is long double; for printf: %f is double, %Lf is long double. There are many other interesting and tricky format specifiers in C language about which you can read on our Format Specifiers in C … If you say to output the next field using a %Lf, then printf() will assume that a long double is waiting there. In C programming, printf() is one of the main output function. filter_none. Output: roots of equation x2 - 4.0000000 x + 3.9999999 = 0 are : for float values: 2.00000 2.00000 for double values: 2.00032 1.99968 This article is contributed by Mandeep Singh. For example, Initialize a double array with int values in C. 1. can someone explain the purpose of %f and %d to me? I am using GNU GCC compiler. Similarly for printing double quotes(” “), using printf() in C we make use of ” \” ” backslash followed by double quote format specifier. What is the argument for printf that formats a long? If a simple double or (heaven forbid!) We have to include “stdio.h” file as shown in below C program to make use of these printf() and scanf() library functions in C language. This is the only correct way for compilers that comply with С99 or later. The function sends formatted output to the screen. 0. f is for float. printf("This is a long double:\t%.9f\n", ld);} Works in Pelles C: This is a long long: 1234567890123456789 This is a long double: 1234567890.1234567 46... but as Czerny already wrote, the long double is not that long - it's an 8-byte double. – AnT Mar 10 '16 at 1:05 [Update] The results would still be the same no matter I use lf, Lf, llf...I am using Code Blocks to compile and run my C program. Which means that lf should be preferred over f for double values. All these double type printing is very confusing in C++. printf() is not type safe. I tried to printf long double float type on different computers including two Windows and one Mac but it turns out that none of them is working as I expected. lf is a perfectly appropriate format specifier for double. Moreover, it was legalized in C99 specifically to fix than annoying inconsistency between format specifiers in fscanf and fprintf. Anyway, many compilers still use the ANSI way and allow printing doubles with the old %f. The code is the following: C double - declaring variables. It has no way to double check. The argument is interpreted as a long double (only applies to floating point specifiers: e, E, f, g and G). Finding what is the current standard requires some more efforts, so I'll stop here. Microsoft VC shows the same behaviour. 464. Scanning data into a multidimensional array. C Output. Related. This is C99 standard. C printf int and double same resault diffrent assumes-1. You might find a gcc or MinGW library that has a 10-byte double. printf("for double values: \n"); double_solve(da, db, dc); return 0; } chevron_right. Declaring a variable is just like with any other type: double price = 9.95; Printing uses the format specifier %lf (%lg, %le or %la are equivalent). 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